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2011 as sum of 10 4th powers

Source: Serbia 2003 1st Grade P1

May 12, 2021
number theoryDiophantine equation

Problem Statement

Find the number of solutions to the equationx14+x24++x104=2011x_1^4+x_2^4+\ldots+x_{10}^4=2011in the set of positive integers.