The equation 3y^2 \plus{} y \plus{} 4 \equal{} 2(6x^2 \plus{} y \plus{} 2) where y \equal{} 2x is satisfied by:
(A)\ \text{no value of }x \qquad(B)\ \text{all values of }x \qquad(C)\ x \equal{} 0\text{ only}
<spanclass=′latex−bold′>(D)</span>all integral values of x only<spanclass=′latex−bold′>(E)</span>all rational values of x only