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2022 CCA Math Bonanza
TB1
Telescoping
Telescoping
Source:
April 28, 2022
Problem Statement
How many positive integer factors does the following expression have?
∑
n
=
1
999
log
10
(
n
+
1
n
)
\sum_{n=1}^{999} \log_{10} \left(\frac{n+1}{n} \right)
n
=
1
∑
999
lo
g
10
(
n
n
+
1
)
2022 CCA Math Bonanza Tiebreaker Round #1
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