MathDB
Today's calculation of Integral 683

Source:

February 25, 2011
calculusintegrationtrigonometrycalculus computations

Problem Statement

Evaluate ∫012(x+1)1−2x2 dx\int_0^{\frac 12} (x+1)\sqrt{1-2x^2}\ dx.
2011 Kyoto University entrance exam/Science, Problem 1B
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