The equation \frac{2x^2}{x\minus{}1}\minus{}\frac{2x\plus{}7}{3}\plus{}\frac{4\minus{}6x}{x\minus{}1}\plus{}1\equal{}0 can be transformed by eliminating fractions to the equation x^2\minus{}5x\plus{}4\equal{}0. The roots of the latter equation are 4 and 1. Then the roots of the first equation are:
<spanclass=′latex−bold′>(A)</span>4 and 1<spanclass=′latex−bold′>(B)</span>only 1<spanclass=′latex−bold′>(C)</span>only 4<spanclass=′latex−bold′>(D)</span>neither 4 nor 1<spanclass=′latex−bold′>(E)</span>4 and some other root