Let Revolution(x)=x3+Ux2+Sx+A, where U, S, and A are all integers and U+S+A+1=1773. Given that Revolution has exactly two distinct nonzero integer roots G and B, find the minimum value of ∣GB∣.Proposed by Jacob Xu
Solution. 392
Notice that U+S+A+1 is just Revolution(1) so Revolution(1)=1773. Since G and B are integer roots we write Revolution(X)=(X−G)2(X−B) without loss of generality. So Revolution(1)=(1−G)2(1−B)=1773. 1773 can be factored as 32⋅197, so to minimize ∣GB∣ we set 1−G=3 and 1−B=197. We get that G=−2 and B=−196 so ∣GB∣=392.