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m^6 = n^(n+1)+n-1

Source: Turkey TST 2013 - Day 2 - P1

April 2, 2013
algebrapolynomialnumber theorygreatest common divisormodular arithmeticnumber theory proposednice problem

Problem Statement

Find all pairs of integers (m,n)(m,n) such that m6=nn+1+nāˆ’1m^6 = n^{n+1} + n -1.
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