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1994 Canada National Olympiad
1
Evaluate Sum - Parity, Factorial, Polynomial
Evaluate Sum - Parity, Factorial, Polynomial
Source: Canadian Mathematical Olympiad - 1994 - Problem 1.
May 13, 2011
factorial
algebra
polynomial
algebra unsolved
Problem Statement
Evaluate
∑
n
=
1
1994
(
(
−
1
)
n
⋅
(
n
2
+
n
+
1
n
!
)
)
\sum_{n=1}^{1994}{\left((-1)^{n}\cdot\left(\frac{n^2 + n + 1}{n!}\right)\right)}
∑
n
=
1
1994
(
(
−
1
)
n
⋅
(
n
!
n
2
+
n
+
1
)
)
.
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