MathDB
n^{5n-1}+n^{5n-2}+n^{5n-3}+n+1

Source: Moldova TST 2022

April 1, 2022
number theory

Problem Statement

Show that for every integer n2n \geq 2 the number a=n5n1+n5n2+n5n3+n+1a=n^{5n-1}+n^{5n-2}+n^{5n-3}+n+1 is a composite number.