Problem 2 Day1
Source: 2011 Armenian Republican Olympiad
August 1, 2016
geometryhexagonrhombus
Problem Statement
Let a hexagone with a diameter be given and let On each side of the hexagon one constructs a isosceles triangle with two equal sides of length . Prove that the sum of the areas of those isoscele triangles is greater than the area of a rhombus with side lengths and a diagonal of length . (The diameter of a polygon is the maximum of the lengths of all its sides and diagonals.)