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Today's Calculation Of Integral
2011 Today's Calculation Of Integral
694
Today's calculation of Integral 694
Today's calculation of Integral 694
Source:
April 21, 2011
calculus
integration
inequalities
logarithms
quadratics
calculus computations
Problem Statement
Prove the following inequality:
∫
1
e
(
ln
x
)
2009
x
2
d
x
>
1
2010
⋅
2011
⋅
2012
\int_1^e \frac{(\ln x)^{2009}}{x^2}dx>\frac{1}{2010\cdot 2011\cdot2012}
∫
1
e
x
2
(
ln
x
)
2009
d
x
>
2010
⋅
2011
⋅
2012
1
created by kunny
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