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2(ZO+O'M+ER)=?, ZOMR rectangle, BR=BE=EO',<BEO'=90^o 2020 BMT Team 16

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January 7, 2022
geometryrectangle

Problem Statement

Let TT be the answer to question 1818. Rectangle ZOMRZOMR has ZO=2TZO = 2T and ZR=TZR = T. Point BB lies on segment ZOZO, O′O' lies on segment OMOM, and EE lies on segment RMRM such that BR=BE=EO′BR = BE = EO', and ∠BEO′=90o\angle BEO' = 90^o. Compute 2(ZO+O′M+ER)2(ZO + O'M + ER).
PS. You had better calculate it in terms of TT.
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