MathDB
2011-china-northern-mathematical-olympiad, p7

Source:

September 29, 2011
trigonometryinequalitiesinequalities unsolvedChina

Problem Statement

In ABC\triangle ABC , then 11+cos2A+cos2B+11+cos2B+cos2C+11+cos2C+cos2A2\frac{1}{1+\cos^2 A+\cos^2 B}+\frac{1}{1+\cos^2 B+\cos^2 C}+\frac{1}{1+\cos^2 C+\cos^2 A}\le 2