MathDB
Permutation of 100 numbers

Source: Canada 2000

March 4, 2006
combinatorics unsolvedcombinatorics

Problem Statement

A permutation of the integers 1901,1902,,20001901, 1902, \cdots, 2000 is a sequence a1,a2,,a100a_1, a_2, \cdots, a_{100} in which each of those integers appears exactly once. Given such a permutation, we form the sequence of partial sums s1=a1,    s2=a1+a2,    s3=a1+a2+a3,    ,  s100=a1+a2++a100.s_1 = a_1,\;\;s_2 = a_1 + a_2,\;\;s_3 = a_1 + a_2 + a_3, \; \ldots\;, \; s_{100} = a_1 + a_2 + \cdots + a_{100}. How many of these permutations will have no terms of the sequence s1,,s100s_1, \ldots, s_{100} divisible by three?