MathDB
1994 AJHSME Problem 14

Source:

July 9, 2011

Problem Statement

Two children at a time can play pairball. For 9090 minutes, with only two children playing at time, five children take turns so that each one plays the same amount of time. The number of minutes each child plays is
(A) 9(B) 10(C) 18(D) 20(E) 36\text{(A)}\ 9 \qquad \text{(B)}\ 10 \qquad \text{(C)}\ 18 \qquad \text{(D)}\ 20 \qquad \text{(E)}\ 36
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