MathDB
2005 JHMT Geometry #5

Source:

August 31, 2023
geometry

Problem Statement

Equilateral triangle ABCABC has AD=DB=FG=AE=EC=4AD = DB = FG = AE = EC = 4 and BF=GC=2BF = GC = 2. From DD and GG are drawn perpendiculars to EFEF intersecting at HH and II, respectively. The three polygons ECGIECGI, FGIFGI, and BFHDBFHD are rearranged to EANLEANL, MNKMNK, and AMJDAMJD so that the rectangle HLKJHLKJ is formed. Find its area. https://cdn.artofproblemsolving.com/attachments/d/4/7e6667f0f0544b6fbc860f8d86c8ceaaf85cc1.png