MathDB
2007 Algebra #1: Floor of Factorials

Source:

June 21, 2012
factorialfloor function

Problem Statement

Compute ⌊2007!+2004!2006!+2005!⌋.\left\lfloor \dfrac{2007!+2004!}{2006!+2005!}\right\rfloor. (Note that ⌊x⌋\lfloor x \rfloor denotes the greatest integer less than or equal to xx.)
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