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Today's Calculation Of Integral
2011 Today's Calculation Of Integral
719
Today's calculation of Integral 719
Today's calculation of Integral 719
Source: 1997 Ehime University entrance exam
June 26, 2011
calculus
integration
trigonometry
calculus computations
Problem Statement
Compute
∫
0
x
sin
t
cos
t
sin
(
2
π
cos
t
)
d
t
\int_0^x \sin t\cos t\sin (2\pi\cos t)\ dt
∫
0
x
sin
t
cos
t
sin
(
2
π
cos
t
)
d
t
.
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