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1997 AJHSME #20 - Probability with Dice

Source:

June 30, 2011
probabilitycountingdistinguishabilityAMC

Problem Statement

A pair of 8-sided dice have sides numbered 1 through 8. Each side has the same probability (chance) of landing face up. The probability that the product of the two numbers that land face-up exceeds 36 is
<spanclass=′latex−bold′>(A)</span> 532<spanclass=′latex−bold′>(B)</span> 1164<spanclass=′latex−bold′>(C)</span> 316<spanclass=′latex−bold′>(D)</span> 14<spanclass=′latex−bold′>(E)</span> 12<span class='latex-bold'>(A)</span>\ \dfrac{5}{32} \qquad <span class='latex-bold'>(B)</span>\ \dfrac{11}{64} \qquad <span class='latex-bold'>(C)</span>\ \dfrac{3}{16} \qquad <span class='latex-bold'>(D)</span>\ \dfrac{1}{4} \qquad <span class='latex-bold'>(E)</span>\ \dfrac{1}{2}
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