1*\infty table - Iran NMO 2001 (Second Round) - Problem6
Source:
October 4, 2010
combinatorics proposedcombinatorics
Problem Statement
Suppose a table with one row and infinite columns. We call each square a room. Let the table be finite from left. We number the rooms from left to . We have put in some rooms some coins (A room can have more than one coin.). We can do below operations:
If in adjacent rooms, there are some coins, we can move one coin from the left room rooms to right and delete one room from the right room.
If a room whose number is or more has more than coin, we can move one of its coins room to right and move one other coin rooms to left. Prove that for any initial configuration of the coins, after a finite number of movements, we cannot do anything more.
Suppose that there is exactly one coin in each room from to . Prove that by doing the allowed operations, we cannot put any coins in the room or the righter rooms.