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Chisinau City MO
1949-56 Chisinau City MO
14
Chisinau MO p14 1949-56 VIII-IX given 1/a+1/b+1/c=1/(a+b+c), sum of two =0
Chisinau MO p14 1949-56 VIII-IX given 1/a+1/b+1/c=1/(a+b+c), sum of two =0
Source:
March 15, 2021
algebra
Sum
Problem Statement
Prove that if the numbers
a
,
b
,
c
a, b, c
a
,
b
,
c
are related by the relation
1
a
+
1
b
+
1
c
=
1
a
+
b
+
c
\frac{1}{a}+ \frac{1}{b}+ \frac{1}{c}= \frac{1}{a+b+c}
a
1
+
b
1
+
c
1
=
a
+
b
+
c
1
then the sum of some two of them is equal to zero.
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