MathDB
angle between 2 equilateral triangles on the same side of line is 60^o

Source: Dutch NMO 2015 p3 seniors

September 7, 2019
geometryEquilateral TriangleEquilateralangles

Problem Statement

Points A,BA, B, and CC are on a line in this order. Points DD and EE lie on the same side of this line, in such a way that triangles ABDABD and BCEBCE are equilateral. The segments AEAE and CDCD intersect in point SS. Prove that ASD=60o\angle ASD = 60^o.
[asy] unitsize(1.5 cm);
pair A, B, C, D, E, S;
A = (0,0); B = (1,0); C = (2.5,0); D = dir(60); E = B + 1.5*dir(60); S = extension(C,D,A,E);
fill(A--B--D--cycle, gray(0.8)); fill(B--C--E--cycle, gray(0.8)); draw(interp(A,C,-0.1)--interp(A,C,1.1)); draw(A--D--B--E--C); draw(A--E); draw(C--D); draw(anglemark(D,S,A,5));
dot("AA", A, dir(270)); dot("BB", B, dir(270)); dot("CC", C, dir(270)); dot("DD", D, N); dot("EE", E, N); dot("SS", S, N); [/asy]