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2014 VTRMC
Problem 1
sum(n^2-2n-4)/(n^4+4n^2+16) from n to ∞
sum(n^2-2n-4)/(n^4+4n^2+16) from n to ∞
Source:
May 10, 2021
Problem Statement
Find
∑
n
=
2
∞
n
2
−
2
n
−
4
n
4
+
4
n
2
+
16
\sum_{n=2}^\infty\frac{n^2-2n-4}{n^4+4n^2+16}
∑
n
=
2
∞
n
4
+
4
n
2
+
16
n
2
−
2
n
−
4
.
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