China Mathematical Olympiad 1988 problem3
Source: China Mathematical Olympiad 1988 problem3
November 5, 2013
combinatorics unsolvedcombinatorics
Problem Statement
Given a finite sequence of real numbers (), we call a segment of the sequence () a “long”(Chinese dragon) and “head” of the “long” if the arithmetic mean of is greater than . (especially if a single item , we still regard as a “long”). Suppose that there is at least one “long” among the sequence (), show that the arithmetic mean of all those items of sequence () that could be “head” of a certain “long” individually is greater than .