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Cute geometry

Source: Caucasus MO 2023, senior, day 2, P8

March 12, 2023
geometry

Problem Statement

Let ABCABC be an acute-angled triangle, and let AA1,BB1,CC1AA_1, BB_1, CC_1 be its altitudes. Points A,B,CA', B', C' are chosen on the segments AA1,BB1,CC1AA_1, BB_1, CC_1, respectively, so that BAC=ACB=CBA=90o\angle BA'C = \angle AC'B = \angle CB'A = 90^{o}. Let segments ACAC' and CACA' intersect at B"B"; points A",C"A", C" are defined similarly. Prove that hexagon AB"CA"BC"A'B"C'A"B'C" is circumscribed.