MathDB
concurrent lines formed by incenter and excenters

Source: Iran 3rd round 2011-geometry exam-p5

September 6, 2011
geometryincentercircumcirclegeometric transformationangle bisectorgeometry proposed

Problem Statement

Given triangle ABCABC, DD is the foot of the external angle bisector of AA, II its incenter and IaI_a its AA-excenter. Perpendicular from II to DIaDI_a intersects the circumcircle of triangle in AA'. Define BB' and CC' similarly. Prove that AA,BBAA',BB' and CCCC' are concurrent.
proposed by Amirhossein Zabeti