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Two consecutive terms in the sequence are squares

Source: Bulgarian National Olympiad 2012 Problem 1

May 21, 2012
number theory proposednumber theory

Problem Statement

The sequence a1,a2,a3a_1,a_2,a_3\ldots , consisting of natural numbers, is defined by the rule: an+1=an+2t(n)a_{n+1}=a_{n}+2t(n) for every natural number nn, where t(n)t(n) is the number of the different divisors of nn (including 11 and nn). Is it possible that two consecutive members of the sequence are squares of natural numbers?