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\frac{a^3}{1-a^2}+\frac{b^3}{1-b^2}+\frac{c^3}{1-c^2}

Source: Moldova TST 2021

September 20, 2021
inequalitiesalgebra

Problem Statement

Positive real numbers aa, bb, cc satisfy a+b+c=1a+b+c=1. Find the smallest possible value of E(a,b,c)=a31a2+b31b2+c31c2.E(a,b,c)=\frac{a^3}{1-a^2}+\frac{b^3}{1-b^2}+\frac{c^3}{1-c^2}.