MathDB
Math Prize 2015 Problem 17

Source:

September 22, 2015

Problem Statement

Let SS be the sum of all distinct real solutions of the equation x+2015=x22015. \sqrt{x + 2015} = x^2 - 2015. Compute 1/S\lfloor 1/S \rfloor. Recall that if rr is a real number, then r\lfloor r \rfloor (the floor of rr) is the greatest integer that is less than or equal to rr.