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P(P(P(x))) = 0 if P(x) = x^2+bx+c (IV Soros Olympiad 1997-98 R3 9.8)

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June 1, 2024
algebrapolynomial

Problem Statement

The equation P(x)=0P(x) = 0, where P(x)=x2+bx+cP(x) = x^2+bx+c, has a single root, and the equation P(P(P(x)))=0P(P(P(x))) = 0 has exactly three different roots. Solve the equation P(P(P(x)))=0.P(P(P(x))) = 0.