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Geometric inequality 1/ab+1/bc+/ca>1/R^2

Source: Nordic MO 2004 Q4

April 20, 2013
inequalitiesgeometrycircumcircleinradiusgeometry unsolved

Problem Statement

Let a,b,ca, b, c be the sides and RR be the circumradius of a triangle. Prove that 1ab+1bc+1ca1R2.\frac{1}{ab}+\frac{1}{bc}+\frac{1}{ca}\ge\frac{1}{R^2}.