MathDB
2016 MMATHS Tiebreaker p2 - >= 504 quadrilaterals at 2016 points

Source:

October 8, 2023
combinatoricscombinatorial geometryMMATHS

Problem Statement

Suppose we have 20162016 points in a 22-dimensional plane such that no three lie on a line. Two quadrilaterals are not disjoint if they share an edge or vertex, or if their edges intersect. Show that there are at least 504504 quadrilaterals with vertices among these points such that any two of the quadrilaterals are disjoint.