MathDB
1999 / 2000 DMM Individual Round - Duke Math Meet

Source:

February 15, 2024
DMMalgebrageometrycombinatoricsnumber theory

Problem Statement

p1. The least prime factor of aa is 33, the least prime factor of bb is 77. Find the least prime factor of a+ba + b.
p2. In a Cartesian coordinate system, the two tangent lines from P=(39,52)P = (39, 52) meet the circle defined by x2+y2=625x^2 + y^2 = 625 at points QQ and RR. Find the length QRQR.
p3. For a positive integer nn, there is a sequence (a0,a1,a2,...,an)(a_0, a_1, a_2,..., a_n) of real values such that a0=11a_0 = 11 and (ak+ak+1)(akak+1)=5(a_k + a_{k+1}) (a_k - a_{k+1}) = 5 for every kk with 0kn10 \le k \le n-1. Find the maximum possible value of nn. (Be careful that your answer isn’t off by one!)
p4. Persons AA and BB stand at point PP on line \ell. Point QQ lies at a distance of 1010 from point PP in the direction perpendicular to \ell. Both persons intially face towards QQ. Person AA walks forward and to the left at an angle of 25o25^o with \ell, when he is again at a distance of 1010 from point QQ, he stops, turns 90o90^o to the right, and continues walking. Person BB walks forward and to the right at an angle of 55o55^o with line \ell, when he is again at a distance of 1010 from point QQ, he stops, turns 90o90^o to the left, and continues walking. Their paths cross at point RR. Find the distance PRPR.
p5. Compute lcm(1,2,3,...,200)lcm(102,103,104,...,200).\frac{lcm (1,2, 3,..., 200)}{lcm (102, 103, 104, ..., 200)}.

p6. There is a unique real value AA such that for all xx with 1<x<31 < x < 3 and x2x \ne 2, Ax2x2+1x26x+8<1999.\left| \frac{A}{x^2-x - 2} +\frac{1}{x^2 - 6x + 8} \right|< 1999. Compute AA.
p7. Nine poles of height 1,2,...,91, 2,..., 9 are placed in a line in random order. A pole is called dominant if it is taller than the pole immediately to the left of it, or if it is the pole farthest to the left. Count the number of possible orderings in which there are exactly 22 dominant poles.
p8. tan(11x)=tan(34o)\tan (11x) = \tan (34^o) and tan(19x)=tan(21o)\tan (19x) = \tan (21^o). Compute tan(5x)\tan (5x).
PS. You had better use hide for answers. Collected [url=https://artofproblemsolving.com/community/c5h2760506p24143309]here.