MathDB
Today's calculation of Integral 9

Source:

May 8, 2005
calculusintegrationlogarithmstrigonometryabsolute valuecalculus computations

Problem Statement

Calculate the following indefinite integrals. [1] ∫(x2+4x−3)2(x+2)dx\int (x^2+4x-3)^2(x+2)dx [2] ∫ln⁡xx(ln⁡x+1)dx\int \frac{\ln x}{x(\ln x+1)}dx [3] ∫sin⁡ (πlog⁡2x)xdx\int \frac{\sin \ (\pi \log _2 x)}{x}dx [4] ∫dxsin⁡xcos⁡2x\int \frac{dx}{\sin x\cos ^ 2 x} [5] ∫1−3x dx\int \sqrt{1-3x}\ dx
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