MathDB
Simple inequality with a+b+c=2

Source: Swiss IMO TST 2003

February 27, 2014
inequalitiesinequalities proposed

Problem Statement

Let a,b,c a,b,c be positive real numbers satisfying a+b+c=2 a+b+c=2 . Prove the inequality 11+ab+11+bc+11+ca2713 \frac{1}{1+ab}+\frac{1}{1+bc}+\frac{1}{1+ca} \ge \frac{27}{13}