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Find the relation between BC^3 and BD^3+BE^3

Source: MTRP 2015 Class 11-Multiple Choice Question: Problem 8 :-

September 21, 2020
geometry

Problem Statement

In ABC\triangle A B C, AB=ACA B=A C and DD is foot of the perpendicular from CC to ABA B and EE the foot of the perpendicular from BB to AC,A C, then
[*] BC3>BD3+BE3BC^3>BD^3+BE^3 [*] BC3<BD3+BE3BC^3 <BD^3+BE^3 [*] BC3=BD3+BE3BC^3=BD^3+BE^3 [*] None of these