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(x^2 - 6x + 13)y = 20,(y^2 - 6y + 13)z = 20, (z^2 - 6z + 13)x = 20

Source: Austrian Polish 1991 APMC

April 30, 2020
system of equationsalgebra

Problem Statement

Find all solutions (x,y,z)(x,y,z) to the system {(x26x+13)y=20(y26y+13)z=20(z26z+13)x=20\begin{cases}(x^2 - 6x + 13)y = 20 \\ (y^2 - 6y + 13)z = 20 \\ (z^2 - 6z + 13)x = 20 \end{cases}