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d(I_1, AD)+ d(I_2, AD)=1/4 BC, bisectors in right ABC (1996 Romania NMO VII p4)

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August 13, 2024
geometryright triangle

Problem Statement

In the right triangle ABCABC (m(A)=90om ( \angle A) = 90^o) DD is the foot of the altitude from AA. The bisectors of the angles ABDABD and ADBADB intersect in I1I_1 and the bisectors of the angles ACDACD and ADCADC in I2I_2. Find the angles of the triangle if the sum of distances from I1I_1 and I2I_2 to ADAD is equal to 14\frac14 of the length of BCBC.