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Greece JBMO TST
2006 Greece JBMO TST
4
min of K(x,y)=16 x^3/y +y^3/x - \sqrt{xy}
min of K(x,y)=16 x^3/y +y^3/x - \sqrt{xy}
Source: Greece JBMO TST 2006 p4
June 16, 2019
algebra
inequalities
minimum
minimum value
Problem Statement
Find the minimum value of
K
(
x
,
y
)
=
16
x
3
y
+
y
3
x
−
x
y
K(x,y)=16\frac{x^3}{y}+\frac{y^3}{x}-\sqrt{xy}
K
(
x
,
y
)
=
16
y
x
3
+
x
y
3
−
x
y
where
x
,
y
x,y
x
,
y
are the real allowed values
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