MathDB
Today's calculation of Integral 767

Source:

November 17, 2011
calculusintegrationtrigonometrycalculus computations

Problem Statement

For 0≤t≤10\leq t\leq 1, define f(t)=∫02π∣sin⁡x−t∣dx.f(t)=\int_0^{2\pi} |\sin x-t|dx. Evaluate ∫01f(t)dt.\int_0^1 f(t)dt.
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