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1=\cos\left( \pi\log_3 (x+6)\right)\cdot\cos\left( \pi\log_3 (x-2)\right)

Source: Romanian District Olympiad 2016, Grade X, Problem 1

October 4, 2018
equationalgebralogarithms

Problem Statement

Solve in the interval (2,) (2,\infty ) the following equation: 1=cos(πlog3(x+6))cos(πlog3(x2)). 1=\cos\left( \pi\log_3 (x+6)\right)\cdot\cos\left( \pi\log_3 (x-2)\right) .