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Prove this inequality on logarithms

Source: 2019 Jozsef Wildt International Math Competition-W. 4

May 18, 2020
inequalitieslogarithms

Problem Statement

If x,y,z,t>1x, y, z, t > 1 then: (logzxtx)2+(logxyty)2+(logxyzz)2+(logyztt)2>14\left(\log _{zxt}x\right)^2+\left(\log _{xyt}y\right)^2+\left(\log _{xyz}z\right)^2+\left(\log _{yzt}t\right)^2>\frac{1}{4}