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im bad at asymptote

Source: November 2021 AMC 10 A/7, 12 A/6

November 11, 2021
Asymptote2021 AMC Fall

Problem Statement

As shown in the figure below, point EE lies on the opposite half-plane determined by line CDCD from point AA so that CDE=110\angle CDE = 110^\circ. Point FF lies on AD\overline{AD} so that DE=DFDE=DF, and ABCDABCD is a square. What is the degree measure of AFE?\angle AFE? [asy] size(6cm); pair A = (0,10); label("AA", A, N); pair B = (0,0); label("BB", B, S); pair C = (10,0); label("CC", C, S); pair D = (10,10); label("DD", D, SW); pair EE = (15,11.8); label("EE", EE, N); pair F = (3,10); label("FF", F, N); filldraw(D--arc(D,2.5,270,380)--cycle,lightgray); dot(A^^B^^C^^D^^EE^^F); draw(A--B--C--D--cycle); draw(D--EE--F--cycle); label("110110^\circ", (15,9), SW); [/asy] <spanclass=latexbold>(A)</span>160<spanclass=latexbold>(B)</span>164<spanclass=latexbold>(C)</span>166<spanclass=latexbold>(D)</span>170<spanclass=latexbold>(E)</span>174<span class='latex-bold'>(A) </span>160\qquad<span class='latex-bold'>(B) </span>164\qquad<span class='latex-bold'>(C) </span>166\qquad<span class='latex-bold'>(D) </span>170\qquad<span class='latex-bold'>(E) </span>174