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DA + AE = KC +CM = AB=BC=CA - All-Russian MO 1997 Regional (R4) 8.3

Source:

September 23, 2024

geometryanglesEquilateral

Problem Statement

On sides

AB

and

BC

of an equilateral triangle

ABC

are taken points

D

and

K

, and on the side

AC

, points

E

and

M

so that

DA + AE = KC +CM = AB

. Prove that the angle between lines

DM

and

KE

is equal to

60^o