MathDB
JBMO TST Moldova Problem 8

Source:

October 14, 2020
number theory

Problem Statement

Find the pairs of real numbers (a,b)(a,b) such that the biggest of the numbers x=b2a12x=b^2-\frac{a-1}{2} and y=a2+b+12y=a^2+\frac{b+1}{2} is less than or equal to 716\frac{7}{16}