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IMO ShortList 1998, combinatorics theory problem 4

Source: IMO ShortList 1998, combinatorics theory problem 4

October 22, 2004
combinatoricsSet systemsSubsetsIMO Shortlist

Problem Statement

Let U={1,2,,n}U=\{1,2,\ldots ,n\}, where n3n\geq 3. A subset SS of UU is said to be split by an arrangement of the elements of UU if an element not in SS occurs in the arrangement somewhere between two elements of SS. For example, 13542 splits {1,2,3}\{1,2,3\} but not {3,4,5}\{3,4,5\}. Prove that for any n2n-2 subsets of UU, each containing at least 2 and at most n1n-1 elements, there is an arrangement of the elements of UU which splits all of them.