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easy inequality with a^2+b^2+c^2=3abc

Source:

June 29, 2012
inequalitiesinequalities proposed

Problem Statement

Let a,b,ca,b,c be positive reals such that a2+b2+c2=3abca^2+b^2+c^2=3abc. Prove that ab2c2+bc2a2+ca2b29a+b+c\frac{a}{b^2c^2}+\frac{b}{c^2a^2}+\frac{c}{a^2b^2} \geq \frac{9}{a+b+c}