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2014 CHMMC Tiebreaker 1 - sum a_i/(k^2+i)=1/k^2

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March 1, 2024
algebraCHMMC

Problem Statement

For a1,...,a5Ra_1,..., a_5 \in R, a1k2+1+...+a5k2+5=1k2\frac{a_1}{k^2 + 1}+ ... +\frac{a_5}{k^2 + 5}=\frac{1}{k^2} for all k{2,3,4,5,6}k \in \{2, 3, 4, 5, 6\}. Calculate a12+...+a56.\frac{a_1}{2}+... +\frac{a_5}{6}.