MathDB
Triangle Problem

Source: Aime 1992#14

February 17, 2006
AoPSwikigeometrygeometry proposed

Problem Statement

In triangle ABCABC, AA', BB', and CC' are on the sides BCBC, ACAC, and ABAB, respectively. Given that AAAA', BBBB', and CCCC' are concurrent at the point OO, and that AOOA+BOOB+COOC=92,\frac{AO}{OA'}+\frac{BO}{OB'}+\frac{CO}{OC'}=92, find AOOABOOBCOOC.\frac{AO}{OA'}\cdot \frac{BO}{OB'}\cdot \frac{CO}{OC'}.