MathDB

Iran TST 2009-Day2-P2

Source:

May 11, 2009

geometryangle bisectorgeometry proposed

Problem Statement

ABC

is a triangle and

AA'

BB'

and

CC'

are three altitudes of this triangle . Let

P

be the feet of perpendicular from

C'

A'B'

, and

Q

is a point on

A'B'

such that QA \equal{} QB . Prove that : \angle PBQ \equal{} \angle PAQ \equal{} \angle PC'C